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Commit 8337d1a8 by trkall
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suur kodune t66

parent 18f308e8
Inline Side-by-side
Showing with 281 additions and 37 deletions
kodunet66_2/k.c 0 → 100644
#include <stdio.h>
#include <stdlib.h>
void sisestus(double*, double*);
void rekursiiv(double*, int *, double, double);
double absoluutv22rtus(double);
double power(double, int);
void push(double*, int*, float);
void v2ljastus(double *, int n);
int main(void)
{
int n = 0;
double x, e;
double * A = malloc(sizeof(double));
sisestus(&x, &e);
push(A, &n, x);
rekursiiv(A, &n, x, e);
v2ljastus(A, n);
// programm lõpetas töö edukalt
return 0;
}
void sisestus(double *x, double *e)
{
do
{
printf("Sisesta reaalarvuline X (|x| < 1)");
scanf("%lf", x);
}
while(!(-1 < *x && *x < 1));
do
{
printf("Sisesta reaalarvuline e (0 < e <1)");
scanf("%lf", e);
}
while(!(0 < *e && *e < 1));
}
void rekursiiv(double *A, int *n, double x, double e)
{
double vahe = *(A+(*n-1)) -*(A+(*n-2));
if((*n) + 1 <= 15 && absoluutv22rtus(vahe) <= e)
{
double vv = power(x,((*n)+1)*2-1)/((double)(((*n)+1))*2-1);
push(A, n, vv);
rekursiiv(A, n, x, e);
}
}
double absoluutv22rtus(double v22rtus)
{
if(v22rtus < 0)
return -1.0f* v22rtus;
else
return v22rtus;
}
double power(double g, int h)
{
if(h > 0)
{
return g * power(g, h-1);
}
else return 1;
}
void v2ljastus(double *stack, int n)
{
char * outputFilename = "l6pptulemus.txt";
FILE *output;
output = fopen(outputFilename, "w");
fprintf(output, "Elementide arv: %d\n", n);
int i;
for(i = 0; i < n; i++)
{
fprintf(output, "%d) %.15lf\n",i, *(stack + i));
}
fclose(output);
}
void push(double *stack, int *n, float v22rtus)
{
double * temp = realloc(stack, sizeof(double)*(*n+1));
if(temp == NULL)
{
printf("Ei saa mälu eraldada!\n");
return;
}
stack = temp;
*n = *n + 1;
*(stack+(*n)-1) = v22rtus;
printf("%d)%.15lf\t%x\n", *n, *(stack +(*n)-1), stack +*n);
}
kodunet66_2/k.o 0 → 100644
File added
maolenloll/kodutoo2.c 0 → 100644
#include <stdio.h>
#include <stdlib.h>
void sisestus(double*, double*);
void rekursiiv(double*, int *, double, double);
double absoluutv22rtus(double);
double power(double, int);
void push(double*, int*, float);
void v2ljastus(double *, int n);
int main(void)
{
int n = 0;
double x, e;
double * A = malloc(sizeof(double));
sisestus(&x, &e);
push(A, &n, x);
rekursiiv(A, &n, x, e);
v2ljastus(A, n);
// programm lõpetas töö edukalt
return 0;
}
void sisestus(double *x, double *e)
{
do
{
printf("Sisesta reaalarvuline X (|x| < 1)");
scanf("%lf", x);
}
while(!(-1 < *x && *x < 1));
do
{
printf("Sisesta reaalarvuline e (0 < e <1)");
scanf("%lf", e);
}
while(!(0 < *e && *e < 1));
}
void rekursiiv(double *A, int *n, double x, double e)
{
double vahe = *(A-*n-1) -*(A-*n-2);
if(((*n) + 1 <= 15) && (absoluutv22rtus(vahe) <= e))
{
double vv = power(x,((*n)+1)*2-1)/((double)(((*n)+1))*2-1);
push(A, n, vv);
rekursiiv(A, n, x, e);
}
}
double absoluutv22rtus(double v22rtus)
{
if(v22rtus < 0)
return -1.0f* v22rtus;
else
return v22rtus;
}
double power(double g, int h)
{
if(h > 0)
{
return g * power(g, h-1);
}
else return 1;
}
void v2ljastus(double *A, int n)
{
char * outputFilename = "l6pptulemus.txt";
FILE *output;
output = fopen(outputFilename, "w");
fprintf(output, "Elementide arv: %d\n", n);
int i;
for(i = 0; i < n; i++)
{
fprintf(output, "%d) %.15lf\n",i, *(A + i));
}
fclose(output);
}
void push(double *A, int *n, float v22rtus)
{
double * temp = realloc(A, sizeof(double)*(*n+1));
if(temp == NULL)
{
printf("Ei saa mälu eraldada!\n");
return;
}
A = temp;
*n = *n + 1;
*(A+(*n)-1) = v22rtus;
printf("%d)%.15lf\t%x\n", *n, *(A +(*n)-1), A +*n);
}
maolenloll/l6pptulemus.txt 0 → 100644
Elementide arv: 15
0) 0.899999976158142
1) 0.243000000715256
2) 0.118097998201847
3) 0.068328127264977
4) 0.043046720325947
5) 0.028528235852718
6) 0.019552813842893
7) 0.013726075179875
8) 0.009810106828809
9) 0.007109745871276
10) 0.005210428033024
11) 0.003853451460600
12) 0.002871592063457
13) 0.002153693931177
14) 0.001624182332307
praktikum 2.8/kodu23.c
#include <stdio.h>
#include <stdlib.h>
int L = 15;
int MAX = 1;
int MIN = 0;
/*
1. klaviatuurilt sisestatakse reaalarvulised X (|X|<1) ja e (0<e<1);
2. rekursiivse funktsiooni abil moodustatakse reaalarvuline massiiv A
elementidega
A1 = X,
A2 = X^3/3,
A3 = X^5/5,
. . .
kuni massiivi A elementide arv L kas vastab tingimusele |A[L] – A[L–1]| <=e või (kui see tingimus ei ole rahuldatud) L = 15;
3. faili F väljastatakse massiivi A elementide arv L ning elemendid
koos indeksitega.
*/
double aste(double, int);
double reku(double);
double absolutevodka(double);
void sisestus(double*, double*);
void rekursiiv(double*, int, double, double);
double absoluutv22rtus(double);
double power(double, int);
int push(double*, int, double);
void v2ljastus(double *, int n);
int main(void)
{
double x;
double e;
double* A = (double*)malloc(sizeof(double*));
printf("Sisestage x:");
scanf("%lf", &x);
printf("\nSisestage e:");
scanf("%lf", &e);
int n = 0;
double x, e;
double * A = (double*)malloc(sizeof(double));
sisestus(&x, &e);
n = push(A, n, x);
rekursiiv(A, n, x, e);
v2ljastus(A, n);
// programm lõpetas töö edukalt
return 0;
}
void sisestus(double *x, double *e)
{
do
{
printf("Sisesta reaalarvuline X (|x| < 1)");
scanf("%lf", x);
}
while(!(-1 < *x && *x < 1));
do
{
printf("Sisesta reaalarvuline e (0 < e <1)");
scanf("%lf", e);
}
while(!(0 < *e && *e < 1));
}
void rekursiiv(double *A, int n, double x, double e)
{
double vahe = 0;
if(n>1)
{
vahe = *(A+(n-1)) -*(A+(n-2));
}
if((n + 1) <= 15 && absoluutv22rtus(vahe) <= e)
{
double vv = power(x,(n+1)*2-1)/((double)((n+1))*2-1);
n = push(A, n, vv);
rekursiiv(A, n, x, e);
}
}
double absoluutv22rtus(double v22rtus)
{
if(v22rtus < 0)
return -1.0f* v22rtus;
else
return v22rtus;
}
double aste(double x, int y)
double power(double g, int h)
{
int i;
for (i = 1;i < y; i++)
if(h > 0)
{
x*=x;
return g * power(g, h-1);
}
return x;
else return 1;
}
double absolutevodka(double x)
void v2ljastus(double *A, int n)
{
if( x < 0)
char * outputFilename = "l6pptulemus.txt";
FILE *output;
output = fopen(outputFilename, "w");
fprintf(output, "Elementide arv: %d\n", n);
int i;
for(i = 0; i < n; i++)
{
x *= -1;
fprintf(output, "%d) %.15lf\n",i, *(A + i));
}
return x;
fclose(output);
}
int push(double *A, int n, double v22rtus)
{
A = (double*)realloc(A, sizeof(double*)*(1 + n));
n++;
*(A+(n-1)) = v22rtus;
printf("%d)%.15lf\t%x\n", n, *(A +(n-1)), *(A + n));
return n;
}
praktikum 2.8/kodu23.o
No preview for this file type
praktikum 2.8/l6pptulemus.txt 0 → 100644
Elementide arv: 1
0) 0.900000000000000
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